1.

Match the element in column A with the valency exhibited by the element given in column B `{:(,"Column A",,,"Column B"),((A),"Neon",(),(a)," "4),((B),"Oxygen",(),(b)," "3),((C),"Potassium",(),(c)," "2),((D),"Boron",(),(d)," "1),((E),"Silicon",(),(d)," "0):}`A. `Atob," " Btoc," " Ctod, " " Dtoe, " " Etoa`B. `Atob," " Btoc," " Ctoa, " " Dtoe, " " Etod`C. `Atoe," " Btod," " Ctoa, " " Dtob, " " Etoc`D. `Atoe," " Btoc," " Ctod, " " Dtob, " " Etoa`

Answer» Correct Answer - 4
`Atoe`
Atomic number of neon is 10 and electronic configuration 2 , 8 valency is zero.
`Btoc`
Atomic number of oxygen is 8 and electronic configuration 2 , 6 valency = 8 - 6 = 2
`Cto d`
Atomic number of potassium is 19 and electronic configuration is 2 , 8 , 8 , valency = 1
`Etoa`
Atomic number of silicon is 14 and electronic cofiguration is 2 , 8 , 4 valency = 4


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