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Methanoic acid, the first member of carboxylic acid series, when warmed with concentrated sulphuric acid decompose in the following way and evolve carbon monoxide. The driving force for this reaction lies in the fact that the `HC-=O^(+)` ion is very unstable acid and thus easily loses `H^(+)`. If acetic acid is replaced by triphenylacetic acid, the products formed will beA. `(C_(6)H_(5))_(3)CH+CO`B. `(C_(6)H_(5))_(3)CH+CO_(2)`C. `(C_(6)H_(5))_(3)COH+CO`D. no reaction |
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Answer» Correct Answer - C `pPh_(3)C-CO OH overset(H_(2)SO_(4))underset(Delta)toPh_(3)C-CHO+Co` |
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