InterviewSolution
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InterviewSolution
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`NADP^(+)` is reduced to NADPH inA. PS-IB. PS-IIC. Calvin cycleD. Non-cyclic photophosphorylation |
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Answer» Correct Answer - D In photosynthesis during non-cyclic photophoshorylation involving both PS-I and PS-II, electrons released during photolysis of water are transferred to PS-II and then PS-I via a series of electron carriers. `P_(700)` of PS-I releases electron after absorbing light energy This electron passes through chlorophyll X, Fe-S, ferredoxin and finally to `NADP^(+).NADP^(+)` combines with `H^(+)` (released during photolysis) with the help of NADP reductase to form NADPH. `NADP^(+)+2e^(-)+H^(+)overset("NADP reductase")toNADPH` |
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