Observations from an experiment on photoelectric effect for the stoppi

1.	Observations from an experiment on photoelectric effect for the stopping potential by varying the incident frequency were plotted. The slope of the linear curve was found to be approximately 4.1 × 10-15 V s. Given that the charge of an electron is 1.6 × 10-19 C, find the value of the Planck’s constant h.
Answer» Data : Slope = 4.1 × 10^-15 V∙s, e = 1.6 ×10^-19 C V₀e = hv – hv₀ ∴ V₀ = \((\cfrac{h}{e})\)v - \((\cfrac{hv_0}{e})\) ∴ Slope = \(\cfrac{h}{e}\) ∴ Planck’s constant, h = (slope) (e) = (4.1 × 10^-15 V∙s)(1.6 × 10^-19 C) = 6.56 × 10 34 J. (as 1 V = \(\cfrac{1J}{1C}\))

Observations from an experiment on photoelectric effect for the stopping potential by varying the incident frequency were plotted. The slope of the linear curve was found to be approximately 4.1 × 10-15 V s. Given that the charge of an electron is 1.6 × 10-19 C, find the value of the Planck’s constant h.

Answer»

Data : Slope = 4.1 × 10^-15 V∙s, e = 1.6 ×10^-19 C

V₀e = hv – hv₀

∴ V₀ = \((\cfrac{h}{e})\)v - \((\cfrac{hv_0}{e})\)

∴ Slope = \(\cfrac{h}{e}\)

∴ Planck’s constant,

h = (slope) (e) = (4.1 × 10^-15 V∙s)(1.6 × 10^-19 C)

= 6.56 × 10 34 J. (as 1 V = \(\cfrac{1J}{1C}\))