InterviewSolution
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Obtain a relation between conductivity (κ) and molar conductivity (∧m). |
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Answer» Conductivity or specific conductance (κ) is the conductance of 1 cm3 of the solution in C.G.S. units, while molar conductivity is the conductance of a solution containing one mole of an electrolyte. Consider C molar solution, i.e., C moles of an electrolyte present in 1 litre or 1000 cm3 of the solution. ∴ C moles of an electrolyte are present in 1000 cm3 solution. ∴ 1 mole of an electrolyte is present in \(\frac{1000}{C}\) cm solution. Now, ∴ Conductance of 1 cm3 of this solution is κ, ∴ Conductance of \(\frac{1000}{C}\) cm3 of the solution is \(\frac{k\times 1000}{C}\) This represents molar conductivity, ∧m. ∴ ∧m = \(\frac{k\times 1000}{C}\)cm2mol-1(in C.G.S units) [ In case of SI units : Consider a solution in which C moles of an electrolyte are present in 1m3 of solution. Conductivity κ is the conductance of 1m3 of solution. ∵ C moles of an electrolyte are present in 1m3 solution. ∴ 1 mol of an electrolyte is present in \(\frac{1}{C}\) solution. ∵ Conductance of 1m3 of this solution is κ. ∴ Conductance of \(\frac{1}{C}\)m3 of the solution is \(\frac{k}{C}\). This represents molar conductivity, ∧m. ∴ ∧m = \(\frac{k}{C}\)Ω-1 m2 mol-1 (In SI units).] |
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