1.

Obtain an exclusive continuous frequency distribution from the following data:

Answer»

Given data is ‘less than’ type cumulative frequency distribution.
Class length = Difference between two adjoining upper boundary points
= 35 – 30 = 5
Now, lower boundary point of a class = upper boundary point – class length
∴ for initial class, lower boundary point = 30 – 5 = 25 and we get initial class 25 – 30.

In this manner we will obtain class for each upper boundary point.
We find the frequency of a class as follows :
Frequency of a class = (‘less than ‘ cumulative frequency of a class) – (‘less than’ cumulative frequency of preceeding class)
Class frequency for upper boundary point 35 = 17 – 0 = 17
In this manner, we will obtain the class frequency for each upper boundary point.

For the given data exclusive continuous frequency distribution is obtained as follows:

Weight ‘less than’ in kg‘Less than’ cumulative frequency cfWeight(in kg)Frequency f
30025-30= 0
351730-3517- 0 = 17
402535-4025 – 17 = 8
454040-4540 – 25 = 15
504845-5048 – 40 = 8
555450-5554 – 48 = 6
605755-6057 – 54 = 3
655960-6559 – 57 = 2
706065-7060 – 59 = 1
Totaln = 60


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