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Obtain the equation of frequency of stationary wave propuced in open pipe and show that all harmonics are possible in it. |
Answer» <html><body><p></p>Solution :In open pipe antiodes are produced at both ends and <a href="https://interviewquestions.tuteehub.com/tag/consecutive-929616" style="font-weight:bold;" target="_blank" title="Click to know more about CONSECUTIVE">CONSECUTIVE</a> antinodes are obtained at <br/> `(lamda)/(2), lamda, (3lamda)/(2), …, (n lamda)/(2)` where,` n = <a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>,2,3,…` <br/> If wavelength is `lamda` for open pipe of length L, then stationary waves will only be produced if `L = ( n lamda )/(2)` <br/> `therefore lamda _(n) = (2L)/(n)` <br/> Frequency of stationlary waves in open pipe, <br/> `(v)/( v _(n )) = (2L)/(n) [ because v = lamda v implies lamda = (v)/(v ) ]` <br/> `therefore v _(n) = (nv)/(2L)...(1)` where v is wave <a href="https://interviewquestions.tuteehub.com/tag/speed-1221896" style="font-weight:bold;" target="_blank" title="Click to know more about SPEED">SPEED</a>. <br/>First 4 harmonics are shown for stationary waves in open pipe in figure, <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_PHY_XI_P2_C15_E01_036_S01.png" width="80%"/> <br/> If wp place `n =1 `in equatin (1), then fundamental or first harmonic is obtained, <br/> `therefore v _(2) = (v)/(2L)` <br/> Second harmonic is obtained by putting `n =2` in equation (1), <br/> `therefore v _(2) = (2v )/( 2L) = v/L OR 2 ((v )/(2L)) = 2v _(1)` <br/> Accordingly by putting `n = 3,4 ,...,n` in equation (1), <a href="https://interviewquestions.tuteehub.com/tag/third-1414358" style="font-weight:bold;" target="_blank" title="Click to know more about THIRD">THIRD</a>, fourth, `...n ^(th)` harmonic can be obtained and corresponding (n-1) overtones are obtained.</body></html> | |