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ObtainNewton.s second law for system of particle and write it.

Answer» <html><body><p></p>Solution :Linear momentum of system of particle <br/> `vecp=mvecv""...(1)` <br/> Taking <a href="https://interviewquestions.tuteehub.com/tag/differention-8395178" style="font-weight:bold;" target="_blank" title="Click to know more about DIFFERENTION">DIFFERENTION</a> on both side with time <br/> `(dvecp)/(dt)=M(dvecv)/(dt)` (where M = constant) <br/> `therefore (dvecp)/(dt)=MvecA""...(2)` <br/> but `MvecA=vec(<a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a>)_(ext""…(3)` <br/> From equation (2) and (3), <br/> `(dvecp)/(dt)=vecF_(ext)""...(4)` is a Newton.s second <a href="https://interviewquestions.tuteehub.com/tag/law-184" style="font-weight:bold;" target="_blank" title="Click to know more about LAW">LAW</a> for the system of particles. <br/> The external force acting on a system is equal to rate of change of <a href="https://interviewquestions.tuteehub.com/tag/total-711110" style="font-weight:bold;" target="_blank" title="Click to know more about TOTAL">TOTAL</a> linear momentum of the system... This is Newton.s second law for a system.</body></html>


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