On a see-saw, two children of masses 50 kg are sitting on one side of it at distances 2 m and 2.5 m respectively from its middle. Where should a man of mass 74 kg sir to balance it?

On a see-saw, two children of masses 50 kg are sitting on one side of

1.	On a see-saw, two children of masses 50 kg are sitting on one side of it at distances 2 m and 2.5 m respectively from its middle. Where should a man of mass 74 kg sir to balance it?
Answer» <html><body><p><strong>Answer:</strong></p><p>2.5 m </p><p></p><p><strong>Explanation:</strong></p><p>Here we have been provided with the values of masses of two children and distances at which they are sitting. </p><p>Those are as <a href="https://interviewquestions.tuteehub.com/tag/follows-994526" style="font-weight:bold;" target="_blank" title="Click to know more about FOLLOWS">FOLLOWS</a>:-</p><ul><li>Mass of first children = 30 <a href="https://interviewquestions.tuteehub.com/tag/kg-1063886" style="font-weight:bold;" target="_blank" title="Click to know more about KG">KG</a> </li><li>Mass of second children = 50 kg </li><li>Distances = 2m and 2.5 m </li></ul><p>As the both children are sitting on left arm. Therefore anticlockwise movement has been <a href="https://interviewquestions.tuteehub.com/tag/produced-592947" style="font-weight:bold;" target="_blank" title="Click to know more about PRODUCED">PRODUCED</a>. </p><p>Let's <a href="https://interviewquestions.tuteehub.com/tag/calculate-412157" style="font-weight:bold;" target="_blank" title="Click to know more about CALCULATE">CALCULATE</a> the anticlockwise moment produced by first children. </p><p>→ 30kgf × 2m </p><p>→ 60 kgf × m </p><p></p><p>Now let us calculate the anticlockwise moment produced by second children. </p><p>→ 50 kgf × 2.5 m </p><p>→ 125 kgf × m </p><p></p><p>Thus total anticlockwise moment produced is as follows:- </p><p>→ Anticlockwise moment produced by first children + anticlockwise moment produced by second children. </p><p>Substituting values,</p><p>→ 60kgf × m + 125 kgf × m </p><p>→ 185 kgf × m </p><p></p><p>Here we are <a href="https://interviewquestions.tuteehub.com/tag/calculating-406701" style="font-weight:bold;" target="_blank" title="Click to know more about CALCULATING">CALCULATING</a> the clockwise moment produced which are as follows, </p><p>But before that let us assume distance from middle by y m. </p><p>Thus, </p><p>→ Clockwise moment = 74 kgf × y m </p><p>→ Clockwise moment = 74 y kgf × m </p><p></p><p>At last we are calculating the distance where should a man of mass 74 kg sir to balance it that I y m. </p><p>Using principal of moments, in equilibrium:- </p><p>Which states that, </p><p>→ Anticlockwise moment = Clockwise moment </p><p>Substituting required values, </p><p>→ 185 = 74 y </p><p>→ y = 185 / 74 </p><p>→ y = 2.5 m </p><p></p><p>Therefore, he should sit at 2.5 m to balance it</p><p></p></body></html>

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On a see-saw, two children of masses 50 kg are sitting on one side of it at distances 2 m and 2.5 m respectively from its middle. Where should a man of mass 74 kg sir to balance it?​

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On a see-saw, two children of masses 50 kg are sitting on one side of it at distances 2 m and 2.5 m respectively from its middle. Where should a man of mass 74 kg sir to balance it?