On analysis, a compound with molar mass 60 g mol1 was found to contain 12 g of carbon, 2 g of hydrogen, and 16 g of oxygen. What is the molecular formula of the compound?

On analysis, a compound with molar mass 60 g mol1 was found to contain

1.	On analysis, a compound with molar mass 60 g mol1 was found to contain 12 g of carbon, 2 g of hydrogen, and 16 g of oxygen. What is the molecular formula of the compound?
Answer» tion:FInd the molecular formula of the compound having 54.5% Carbon, 9.23% Hydrogen. (Vapour density=44g/l, Molar MASS=88 g/mol)The compound has 54.5% Carbon, 9.23% Hydrogen. The remaining is Oxygen.100 g of the compound will have 54.5 g C, 9.23 g H and 100−54.5−9.23=36.27 g O.The atomic MASSES of C, H and O are 12 g/mol, 1 g/mol and 16 g/mol respectively. The number of moles of C= 12 g/mol54.5 g =4.54 mol.The number of moles of H= 1 g/mol9.23 g =9.23 mol.The number of moles of O= 16 g/mol36.27 g =2.27 mol.Mole ratio C:H:O=4.54:9.23:2.27=2:4:1The empirical formula of the compound is C 2 H 4 OTHE empirical formula mass =2(12)+4(1)+16=44 g/molMolar mass of the compound is 88 g/mol. It is twice the empirical formula mass of 44 g/mol.The molecular formula of the compound is C 4 H 8 O 2