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One end of a long string of linear mass density10^(-2) kg m^(-1) is connected to an electrically driven tuning fork of frequency 150 Hz. The other end passes over a pulley and is tied to a pan containig a massof 90 kg. the pulley end absorbs all the incoming energy so that reflected waves from this end have neglidible amplitude , At t =0, the left end (fork end ) of the string is at x=0 has a transverse displacement of 2.5 cm and is moving along positive y-direction. the amplitude of the wave is 5 cm. write down the transverse displacement y (in cetimetres) as function of x(in metres) and t (in seconds ) that describes the wave on the string.

Answer» <html><body><p></p>Solution :`theta=pi//<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>=sqrt(T//mu)=sqrt(<a href="https://interviewquestions.tuteehub.com/tag/900-341675" style="font-weight:bold;" target="_blank" title="Click to know more about 900">900</a>)/(0.01)=<a href="https://interviewquestions.tuteehub.com/tag/300-305868" style="font-weight:bold;" target="_blank" title="Click to know more about 300">300</a> m//s` <br/> <a href="https://interviewquestions.tuteehub.com/tag/frequency-465761" style="font-weight:bold;" target="_blank" title="Click to know more about FREQUENCY">FREQUENCY</a> `=150 Hz` <br/> `:.lambda=(v)/(f)=(300)/(150)=2m`<br/> Then equation will be <br/> `y=A sin{2pi((t)/(T)-(x)/(lambda))+theta}` <br/> `=5 sin{2pi(150t-(x)/(2))+(pi)/(6)}` <br/> `=5 sin{pi(300t-x)+(pi)/(6)}`</body></html>


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