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One Kg of steam at 1.5MPa and 400ºC in a piston – cylinder device is cooled at constant pressure. Determine the final temperature and change in volume. If the cooling continues till the condensation of two – third of the mass. |
Answer» Given that Mass of steam m = 1kg Pressure of steam P1 = 1.5MPa = 15bar Temperature of steam T1 = 400ºC From superheated steam table At P1 = 15bar, T1 = 400ºC Å1 = 0.1324 m3/kg Å2 = (2 x 0.1324)/3 = 0.0882 m3/kg Change in volume “Å = Å1 - Å2 = 0.1324 – 0.0882 = 0.0441 m3/kg The steam is wet at 15bar, therefore, the temperature will be 198.32ºC. |
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