InterviewSolution
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InterviewSolution
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One mole of a present in a closed vessel undergoes decay as `""_(z)""^(m)Ato""_(Z-4)""^(m-8)B+2""_(2)""^(4)He`. The volume of He collected at NTP a fter 20 days is (`t""_(1//2)=10`days)a)11.2 litreb)22.4 litrec)33.6 litred)67.2 litre |
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Answer» We know that, `N = N_(0) ((1)/(2))^(n)` N = remaining mole of A `N = 1 ((1)/(2))^(2) = (1)/(4)` Number of decayed moles `= 1 - (1)/(4) = (3)/(4)` Number of moles of helium formed `= 2 xx` Number of decayed moles of `A = 2 xx (3)/(4) = (3)/(2)` Volume of helium at STP `= (3)/(2) xx 22.4 = 33.6` litre |
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