One mole of un known compound was treated with excess of water and resulted in the evolution of two moles of a readily combustle gas . The resulting solution was treated with `CO_(2)` and resulted in the formation of white turbidity . The unknown compound isA. `Ca`B. `CaH_(2)`C. `Ca(OH)_(2)`D. `Ca(NO)_(2)`

One mole of un known compound was treated with excess of water and res

1.	One mole of un known compound was treated with excess of water and resulted in the evolution of two moles of a readily combustle gas . The resulting solution was treated with `CO_(2)` and resulted in the formation of white turbidity . The unknown compound isA. `Ca`B. `CaH_(2)`C. `Ca(OH)_(2)`D. `Ca(NO)_(2)`
Answer» Correct Answer - B `underset(" 1 mole") (Ca) + 2 H_(2)O to Ca(OH)_(2) + underset("1 mole")(H_(2))` `underset("1 mole")(CaH_(2)) + 2 H_(2) O to Ca(OH)_(2) + underset("2 moles")(2 H_(2))` `Ca(OH)_(2) + CO_(2) underset(" White turbidity")(CaCO_(3)) + H_(2)O` Since both Ca and `CaH_(2)` react with `H_(2)O` to produce combustible `H_(2)` gas but 1 mole of `CaH_(2)` produces two moles of `H_(2)` , therefore , option (b) is correct .

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