InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
One of the diagonals of a rhombus is thrice as the other. If the sum of the length of the diagonals is 24 cm, then find the area of the rhombus. |
|
Answer» Let one of the diagonals of rhombus be ‘d1’ cm and the other be d2 cm. Give d1 = 3 x d2 Also d1 + d2 = 24 cm ⇒ 3d2 + d2 = 24 4d2 = 24 d2 = \(\frac{24}{4}\) d2 = 6 cm d1 = 3 x d2 = 3 x 6 d1 = 18 cm ∴ Area of the rhombus = \(\frac{1}{2}\) x d1 x d2 sq. units = \(\frac{1}{2}\) x 18 x 6 cm2 = 54 cm2 Area of the rhombus = 54 cm2 |
|