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Out of 7 consonants and 4 vowels, how many words of 3 consonants and 2 vowels can be formed? |
Answer» In this problem first, we have to select consonants and vowels. Then we arrange a five-letter word using 3 consonants and 2 vowels. Therefore here both combination and permutation involved. The number of ways of selecting 3 consonants from 7 is 7C3. The number of ways of selecting 2 vowels from 4 is 4C2. The number of ways selecting 3 consonants from 7 and 2 vowels from 4 is 7C3 x 4C2. Now with every selection number of ways of arranging 5 letter word = 5! x 7C3 x 4C2 = 120 x \(\frac{7\times6\times5}{3\times2\times1}\) x \(\frac{4\times3}{2\times1}\) = 25200 |
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