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Oxidation states of `P` in `H_(4)P_(2)O_(5), H_(4)P_(2)O_(6)` and `H_(4)P_(2_)O_(7)`, respectively areA. `+3,+5` and +4B. `+5,+3` and +4C. `+5,+4` and +3D. `+3,+4` and `+5` |
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Answer» Correct Answer - D Oxidation state of H is `+1` and that of O is `-2`. Let the oxidation state of P in the given compounds is x. In `H_(4)P_(2)O_(5)` `(+1)xx4+2xx x+(-2)xx5=0` `4+2x - 10 = 0` `2x = 6` `:. x = +3` In `H_(4)P_(2)O_(6)` `(+1) xx4+2xx x + (-2)xx6=0` `4+2x-12=0` `2x=8` `:. x = +4` In `H_(4)P_(2)O_(7)` `(+1)xx4+2xx x + (-2)xx7=0` `4+2x-14=0` `2x=10` `:. x = +5` Thus the oxidation states of `P` in `H_(4)P_(2)O_(5)`. `H_(4)P_(2)O_(6)` and `H_(4)P_(2)O_(7)` are `+3,+4` and `+5` respectively. |
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