p(x)=3x²-1,x=-1/√3

1.	p(x)=3x²-1,x=-1/√3
Answer» As we know that x=1/√3,so by the factor theorem,1/√3 is a factor of p(x) if p(1/√3)=0.now,p(1/√3)=3×(1/√3)wholesquare-1.So,p(x)=1-1.Thus,p(x)=0.Hence,1/√3 is a factor of p(x).

Discussion