Panas has 15 yellow , pink andwhite balls in his bag . Numberof each ballsis different in thebag ,Differencebetweenyellow balland pinkball is same as difference between pinkball and white ball,probability of selecting one white ball fromthebag is greater than0.2, thennumberofwhite balls in the bag can be {:("(A)"3,(B)4),("( C)"5,(D)7),("( E)"9,):}

Panas has 15 yellow , pink andwhite balls in his bag . Numberof each b

1.	Panas has 15 yellow , pink andwhite balls in his bag . Numberof each ballsis different in thebag ,Differencebetweenyellow balland pinkball is same as difference between pinkball and white ball,probability of selecting one white ball fromthebag is greater than0.2, thennumberofwhite balls in the bag can be {:("(A)"3,(B)4),("( C)"5,(D)7),("( E)"9,):}
Answer» Only B,C,D and E Only B,D,E All A,B,C,D and E Only C,D,E Solution :Let numberof yellow , pinkand whiteballsbe x,y andz respectively ATQ, `x-y=y-z` `y=(x+z)/(2) or 2y=x+z` `and (z)/(x+y+z)GT 0.2` `(z)/(3y)gt (1)/(5)` `5zgt 3y` `"If" y=5,then z gt 3` If `y= 10 , thenz gt 6,` but this isn'tpossible hence, `{:("yellow","pink","WHITE"),(6,5,4),(4,5,6),(3,5,7),(2,5,8),(1,5,9):}` ,5,5,5 isn't possibleas number of ballsis different hence , fromgivennumbers only (B),(D) and ( E) CANBE thepossible . SO, option ,(B) is thecorrect answer.