Particle A is moving with a constant velocity of `V_(A) = 50 ms^(–1)` in positive x direction. It crossed the origin at time `t = 10 s`. Another particle B started at `t = 0` from the origin and moved with a uniform acceleration of `a_(B) = 2 ms^( –2)` in positive x direction. (a) For how long was A ahead of B during the subsequent journey? (b) Draw the position (x) time (t) graph for the two particles and mark the interval for which A was ahead of B.

Particle A is moving with a constant velocity of `V_(A) = 50 ms^(–1)

1.	Particle A is moving with a constant velocity of `V_(A) = 50 ms^(–1)` in positive x direction. It crossed the origin at time `t = 10 s`. Another particle B started at `t = 0` from the origin and moved with a uniform acceleration of `a_(B) = 2 ms^( –2)` in positive x direction. (a) For how long was A ahead of B during the subsequent journey? (b) Draw the position (x) time (t) graph for the two particles and mark the interval for which A was ahead of B.
Answer» Correct Answer - (a) `10 sqrt(5) s`

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