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pole, given that I em' of iron has approximately 8g mass. (Use Tt-3.14)7. A solid consisting of a right circular cone of height 120 cm and radius 60 cm standing one of water left in the cylinder, if the radiusa hemisphere of radius 60 cm is placed upright in a right circular cylinder full of watesuch that it touches the bottom. Find the volumof the cylinder is 60 cm and its height is 180 cm.

Answer»

Answer:

Step-by-step explanation:

We need to calculate the volume of the solid figure

The figure is made of two shapes:

Conical partHemispherical partStep 1 : Calculate the volume of the conical part:

The following is the formula of calculating the volume of a cone:

1/3 πr²H

Volume = 1/3 × 3.142 × 60 × 60 x 120

= 452448 cm³

Step 2: Calculate the volume of the hemispherical part

Formula for calculating the volume of a hemisphere

2/3πr³

Volume = 2/3 × 3.142 × 60 × 60 × 60

= 452448 cm³

∴ The volume of the solid is:

452448 + 452448 = 904896 cm³

Volume = 904896 cm³

Step 3: Find the volume of the cylinder:

Formula of calculating the volume of a cylinder

πr²H

Volume = 3.142 × 60 × 60 × 180

= 2036016 cm³

⇒The volume of the water remaining in the cylinder will the volume of the solid subtracted from the volume of the cylinder.

2036016 cm³ - 904896 cm³ = 1131120 cm³

The volume of the water left is 1131120 cm³



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