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Position vector of a particle as a function of time is given by, →R=(a sin ωt)^i+(a cos ω t)^j+(b sin ω0t)^k.The particle appears to be performing simple harmonic motion along z direction, to an observer moving in xy plane. The distance travelled by the observer while he sees the particle completing one oscillation is 2πax[ωω0]. The value of x is

Answer» Position vector of a particle as a function of time is given by,
R=(a sin ωt)^i+(a cos ω t)^j+(b sin ω0t)^k.The particle appears to be performing simple harmonic motion along z direction, to an observer moving in xy plane. The distance travelled by the observer while he sees the particle completing one oscillation is 2πax[ωω0].
The value of x is


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