InterviewSolution
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InterviewSolution
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Pressure of 1 g of an ideal gas A `27^(@)C` is found to be 2 bar. When 2 g of another ideal gas B is introduced in the same flask at same temperature, the pressure becomes 3 bar. Find the relationship between their molecular masses. |
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Answer» Suppose molecular masses of A and B `M_(A)` and `M_(B)` respectively. Then their number of moles will be `m_(A)=(1)/(M_(A))," "n_(B)=(2)/(M_(B))` `P_(A)=2"bar", P_(A)+P_(B)=3"bar",i.e.,P_(B)=1"bar"` Applying the relation, PV=nRT `P_(A)V=n_(A)RT,P_(B)V=n_(B)RT` `:." " (P_(A))/(P_(B))=(n_(A))/(n_(B))=(1//M_(A))/(2//M_(B))=(M_(B))/(2M_(A))` `"or " (M_(B))/(M_(A))=2xx(P_(A))/(P_(B))=2xx(2)/(1)=4" " or " " M_(B)=4M_(A)`. |
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