pressure of 1 mole of an ideal gas undergoing a process is P=P_0/(1+\l – InterviewSolution

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1.	pressure of 1 mole of an ideal gas undergoing a process is P=P_0/(1+\lbrack V/V_{0_{}}\rbrack^n),where P_0 and V_0 are cons†an ts.The temperature of the gas at volume V=V_0 is ?
Answer» pressure of 1 mole of an ideal gas undergoing a process is P=P_0/(1+\lbrack V/V_{0_{}}\rbrack^n),where P_0 and V_0 are cons†an ts.The temperature of the gas at volume V=V_0 is ?

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