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Prove that √3 ber. please dont spam |
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Answer» Answer: If possible , let 3
be a rational number and its simplest form be b a
then, a and b are integers having no COMMON factor other than 1 and b =0. Now, 3 ⟹3= b. a 2 2
(On squaring both sides ) or, 3b 2 =a 2 .......(i)⟹3 DIVIDES a 2 (∵3 divides 3b 2 )⟹3 divides a Let a=3c for some integer c Putting a=3c in (i), we get or, 3b 2 =9c2 ⟹b 2 =3c 2⟹3 divides b 2 (∵3 divides 3c 2 )⟹3 divides a Explanation: Hope it's helpful to you but don't know it is right answer or no.. |
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