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prove that the line 2x + y = 1 is a tangent to the circle x^2+y^2+6x-4y+8=0. |
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Answer» Solution :`x^2+y^2+6x-4y+8=0` `therefore` g = 3, F = -2, c = 8 `therefore` Centre at (-3, 2) and radius is sqrt(g^2+f^2-c) = sqrt(9+4-8) = sqrt5` Distance of the centre from the line 2X + y -1 = 0 is `abs((2(-3)+1xx2-1)/sqrt(4+1))` = `abs((-6+2-1)/sqrt5) = sqrt5` `therefore` The line touches the CIRCLE` |
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