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Quantity of heat gained by 100 kg of iron in raising its temperature by 10^(@)C is 11xx10^(4)cal. If a heater can supply heat at the rate of 1000 J s^(-1), how much time does it take to heat an iron block of mass 2.5 kg when the mecury level in a Fahrenheit thermometer rises by 45 divisions. |
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Answer» Solution :Find the mass of the iron from GIVEN data. Find the amoun of heat gained by iron to RAISE its temperature by `10^(@)C`, from the given data. Find the specific heat of the iron fro the formula, `Q=msDeltatheta` find the corresponding temperature change in CELSIUS scale, when there is temperature change of 45 divisions in Fahrenheit scale from the formula `(DeltaC)/(100)=(DeltaF)/(180)` . . .(1) Fdin how much amount of heat energy 'Q' is REQUIRED for 2.5 kg iron block to increase its temperatrue by `'DeltaC'` makeuse of `Q'=2.5xxsxxDeltaC`. . .(2) Check the units of Q' If it in calorie, convert it into joule. then, find the amount of time taken to PRODUCE Q' by dividing Q' by 1000. |
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