1.

Quantity of heat gained by 100 kg of iron in raising its temperature by 10^(@)C is 11xx10^(4)cal. If a heater can supply heat at the rate of 1000 J s^(-1), how much time does it take to heat an iron block of mass 2.5 kg when the mecury level in a Fahrenheit thermometer rises by 45 divisions.

Answer»

Solution :Find the mass of the iron from GIVEN data.
Find the amoun of heat gained by iron to RAISE its temperature by `10^(@)C`, from the given data.
Find the specific heat of the iron fro the formula, `Q=msDeltatheta`
find the corresponding temperature change in CELSIUS scale, when there is temperature change of 45 divisions in Fahrenheit scale from the formula
`(DeltaC)/(100)=(DeltaF)/(180)` . . .(1)
Fdin how much amount of heat energy 'Q' is REQUIRED for 2.5 kg iron block to increase its temperatrue by `'DeltaC'`
makeuse of `Q'=2.5xxsxxDeltaC`. . .(2)
Check the units of Q'
If it in calorie, convert it into joule.
then, find the amount of time taken to PRODUCE Q' by dividing Q' by 1000.


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