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R relation on the set Z of integers and it is given by `(x,y) in R |x-y| |
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Answer» Correct Answer - B For any `x in Z`, we have `|x-x|=0le1` `therefore |x-x|le1 " for all x"inZ` `implies (x, x) in R " for all x"in Z` implies R is reflexive on Z. Let `(x, y) in R`. Then, `|x-y|le1implies|y-x|le1implies(y,x)inR` Thus, `(x,y) in Rimplies(y,x)inR`. So, R is a symmetric relation on Z. We observe that `(1, 0) in R` and `(0, -1) in R`, but `(1, -1) cancelin R`. So, R is not a transitive relation on Z. |
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