1.

R relation on the set Z of integers and it is given by `(x,y) in R |x-y|

Answer» Correct Answer - B
For any `x in Z`, we have
`|x-x|=0le1`
`therefore |x-x|le1 " for all x"inZ`
`implies (x, x) in R " for all x"in Z`
implies R is reflexive on Z.
Let `(x, y) in R`. Then,
`|x-y|le1implies|y-x|le1implies(y,x)inR`
Thus, `(x,y) in Rimplies(y,x)inR`.
So, R is a symmetric relation on Z.
We observe that `(1, 0) in R` and `(0, -1) in R`, but `(1, -1) cancelin R`.
So, R is not a transitive relation on Z.


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