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Radioactive disintegration of `._(88)Ra^(226)` `Ra overset(-alpha)rarr Rn overset(-alpha)rarr RnA overset(-alpha)rarr RaB overset(-beta)rarr RaC` Determine the mass number, atomic number, and group in periodic table for `RaC`. |
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Answer» Parent element is `._(88)^(226)Ra`. atomic mass = 226 Atomic number = 88 RaC is formed after the emission of 3 alpha particles. Mass of 3 alpha particles `= 3 xx 4 = 12` So, Atomic mass of RaC = (226 - 12) = 214 With emission of one `alpha`particle atomic number is decreased by 2 and with the emission of one `beta`-particle, atomic number is increased by 1. So, Atomic number of RaC = `88 - (3 xx 2) + 1 = 83` |
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