Redox reactions play a pivotyal role in chemistry and biology. The values of standard redox potential `(E^(@))` of two half-cell reactions decide which way the reaciton is expected to proced. A simple exampler is a Daniel cell in which zinc goes into solution and copper gerts deposited. Given below are a set of half-cell reactions (acidic medium) along with their `E^(@)` (`V` with respect to normal hydrofgen electrode) values. Using this data : `I_(2) + 2e^(-) rarr 2I^(-)" " E^(@) = 0.54`, `CI_(2) + 2e^(-) rarr 2CI^(-) " "E^(@) = 1.36`,. `Mn^(3+) + e^(-) rarr Mn^(2+) " "E^(@) = 1.50`, `Fe^(3+) + e^(-) rarr Fe^(2+)" " E^(@) = 0.77`, `O_(2) + 4H^(+) + 4e^(-) rarr 2H_(2)O " "E^(@) = 1.23`, Soldium fusion extract, obtained from aniline, on treatment with iron `(II)` sulphatge and `H_(2)SO_(4)` in presence of air gives a Prussion bule precipitate. The blue colour is due to the formation of :A. `Fe_(4)[Fe(CN)_(6)]_(3)`B. `Fe_(3)[Fe(CN)_(6)]_(2)`C. `Fe_(4)[Fe(CN)_(6)]_(2)`D. `Fe_(3)[Fe(CN)_(6)]_(3)`

Redox reactions play a pivotyal role in chemistry and biology. The val

1.	Redox reactions play a pivotyal role in chemistry and biology. The values of standard redox potential `(E^(@))` of two half-cell reactions decide which way the reaciton is expected to proced. A simple exampler is a Daniel cell in which zinc goes into solution and copper gerts deposited. Given below are a set of half-cell reactions (acidic medium) along with their `E^(@)` (`V` with respect to normal hydrofgen electrode) values. Using this data : `I_(2) + 2e^(-) rarr 2I^(-)" " E^(@) = 0.54`, `CI_(2) + 2e^(-) rarr 2CI^(-) " "E^(@) = 1.36`,. `Mn^(3+) + e^(-) rarr Mn^(2+) " "E^(@) = 1.50`, `Fe^(3+) + e^(-) rarr Fe^(2+)" " E^(@) = 0.77`, `O_(2) + 4H^(+) + 4e^(-) rarr 2H_(2)O " "E^(@) = 1.23`, Soldium fusion extract, obtained from aniline, on treatment with iron `(II)` sulphatge and `H_(2)SO_(4)` in presence of air gives a Prussion bule precipitate. The blue colour is due to the formation of :A. `Fe_(4)[Fe(CN)_(6)]_(3)`B. `Fe_(3)[Fe(CN)_(6)]_(2)`C. `Fe_(4)[Fe(CN)_(6)]_(2)`D. `Fe_(3)[Fe(CN)_(6)]_(3)`
Answer» Correct Answer - A `Na + C + N rarr NaCN` `Fe^(2+) + 6CN^(-) rarr [Fe(CN)_(6)]^(4-)` `4Fe^(3+) + 3[Fe(CN)_(6)]^(4-) rarr underset("Prussion blue")(Fe_(4)[Fe(CN)_(6)]_(3darr)`

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Define molar conductivity of a solution and explain how molar conductivity changes with change in concentration of a solution for a weak and a strong electrolyte.
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Based on the data given below, the correcy order of reducing power is: `Fe_((aq.))^(3+) + e rarr Fe_((aq.))^(2+), E^(@) = +0.77 V` `Al_((aq.))^(3+) + 3e rarr Al_((s)), E^(@) = -1.66 V` `Br_(2(aq.)) + 2e rarr 2Br_((aq.))^(-), E^(@) = +1.08 V`A. `Br^(-) lt Fe^(2+) lt Al`B. `Fe^(2+) lt Al lt Br^-`C. `Al lt Br^(-) lt Fe^(2+)`D. `Al lt Fe^(2+) lt Br^(-)`
What are elementary reactions ?

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