Resistance of a conductivity cell filled with a solution of an electrolyte of concentration 0.1M is `100Omega`. The conductivity of this solution is 1.29 `S m^(-1)`. Resistance of the same cell when filled with 0.2M of the same solution is `520Omega`. the molar conductivity of `0.02`M solution of the electrolyte will beA. `1.24xx10^(-4)Sm^(2)"mol"^(-1)`B. `12.4xx10^(-4)S m^(2) "mol"^(-1)`C. `124xx10^(-4)S m^(2)"mol"^(-1)`D. `1240xx10^(-4)S m^(2)"mol"^(-1)`

Resistance of a conductivity cell filled with a solution of an electro

1.	Resistance of a conductivity cell filled with a solution of an electrolyte of concentration 0.1M is `100Omega`. The conductivity of this solution is 1.29 `S m^(-1)`. Resistance of the same cell when filled with 0.2M of the same solution is `520Omega`. the molar conductivity of `0.02`M solution of the electrolyte will beA. `1.24xx10^(-4)Sm^(2)"mol"^(-1)`B. `12.4xx10^(-4)S m^(2) "mol"^(-1)`C. `124xx10^(-4)S m^(2)"mol"^(-1)`D. `1240xx10^(-4)S m^(2)"mol"^(-1)`
Answer» Correct Answer - C Cll constant =`x xxR` `=1.29S m^(-1)xx100Omega=129m^(-1)` In the 2nd case `x=("cell constant")/("Resistance")` `=(129m^(-1))/(520Omega)= 0.248Omega^(-1)m^(-1)` `^^_(m)=(x)/("molarity")=(0.248Omega^(-1)m^(-1))/(0.02xx10^(3)"mol"m^(-1))` `=124xx10^(-4)Sm^(2)"mol"^(-1)`

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