Resistance of a conductvity cell filled with a solution of an electrolyte of concentration 0.1 M is 100 `Omega`. The conductivity of this solution is 1.29 `Sm^(-1)`. Resistance of the same cell when filled with 0.02M of the same solution is `520 Omega`. the molar conductivity of 0.02M solution of the electrolyte will be:A. `124xx10^(-4) S m^(2) mol^(-1)`B. `1240xx10^(-4) S m^(2) mol^(-1)`C. `1.24xx10^(-4) S m^(2) mol^(-1)`D. `12.4xx10^(-4) S m^(2) mol^(-1)`

Resistance of a conductvity cell filled with a solution of an electrol

1.	Resistance of a conductvity cell filled with a solution of an electrolyte of concentration 0.1 M is 100 `Omega`. The conductivity of this solution is 1.29 `Sm^(-1)`. Resistance of the same cell when filled with 0.02M of the same solution is `520 Omega`. the molar conductivity of 0.02M solution of the electrolyte will be:A. `124xx10^(-4) S m^(2) mol^(-1)`B. `1240xx10^(-4) S m^(2) mol^(-1)`C. `1.24xx10^(-4) S m^(2) mol^(-1)`D. `12.4xx10^(-4) S m^(2) mol^(-1)`
Answer» Correct Answer - A `kappa=1/Rxxl/A` `1.29=1/100xxl/A` `l/A=129 m^(-1)` `Lambda_(m)=kappaxx1000/M` `=(1/Rxxl/A)xx1000/M` `=(1/520xx129)xx1000/0.02xx10^(-6)` `=124xx10^(-4) S m^(2) mol^(-1)`

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