1.

Select electrophiles out of the following : `H^(+), Na^(+), Cl^(-), C_(2)H_(5)OH, AlCl_(3), SO_(3), CN^(-), CH_(3)CH_(2)^(+), : C Cl_(2), R-X`

Answer» Electrophiles are : `H^(+), AlCl_(3), SO_(3), CH_(3)CH_(2)^(+), :C Cl_(2), R-X`.
In `SO_(3), O = underset(+)overset(O)overset(||)(S)-O^(-)`, S atom carries a positive charge and hence acts as an electrophile. In `AlCl_(3)`, Al atom has six and in : `C Cl_(2), C` atom has six electrons in the valence shell and hence each one of these needs two more electrons to complete their respective octets. As a result, both `AlCl_(3)` and `:C Cl_(2)` act as electrophiles. `overset(delta+)(R)-overset(delta-)(X)`, due to greater electronegativity of X, R carries a partial positive charge and hence acts as an electrophile.
`Na^(+)` ion does not act as an electrophile even though it has +ve charge. The reason being that it has already an octet of electrons in the valence shell. Further, `Na^(+)` cannot expand its valence shell beyond 8 electrons since it does not have d-orbitals.


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