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    				| 1. | Several capacitors are connected as shown in. If the charge on the `5 muF` capacitor is `120 muC`, the potential between points A and D` is . | 
| Answer» Correct Answer - `5.33 V` Charge across `5muF` capacitor is `10muC`, Therefore, potential difference across `5 muF`. Cpacitor is `q/C=(10xx10xx10^(-6))/(5xx10^(-6))-=2 V` As `3,4`, and `5muF` capacitors are in parallel, so potential difference across each of the them equals `2V`. Charge on `3 muF` capacitor is `CV=3xx10^(-6)xx2=6 muC` Charge on `4 muF` capacitor is `4xx10^(-6)xx2=8 muC` Total charge flowing in upper branch of circuit is `10 muC+6muC+ 8muC=24 muC` Potential difference across `C_(2)` is `24 muC/F=6 V`. Total potential differecnce across AB is `6+2=8 V`. Equivalent capacitance of lower branch of circuit is `(6xx3)/(6+3)=2 muF` So, charge flowing is `2xx10^(-6)xx8=16 muC` herefore, potential difference between `A` and `C`is `(16muC)/(3 muF)=(16)/3=5.33 V`. | |