InterviewSolution
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InterviewSolution
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Show that `sqrt(2)` and `-2sqrt(2)` are the roots of the equation `x^(2)+sqrt(2)x-4=0.` |
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Answer» The given equation is `x^(2)+sqrt(2)x-4=0.` Putting `x=sqrt(2)` in the given equation, we get `LHS=(sqrt(2))^(2)+(sqrt(2)xxsqrt(2))-4=(2+2-4)=0=RHS.` `:." "sqrt(2)` is a root of the given equation. Putting `x=-2sqrt(2)` in the given equation, we get `LHS=(-2sqrt(2))^(2)+sqrt(2)xx(-2sqrt(2))-4=(8-4-4)=0=RHS.` `:." "-2sqrt(2)` is a root of the given equation. Hence, `sqrt(2)` and `-2sqrt(2)` are the roots of the given equation. |
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