1.

Show that, the change in frequency of sound during the motion of the source towards audience is more than that when audience moves towards source with same velocity.

Answer»

Solution :Natural frequency of the source `=N,`
VELOCITY of sound `=V,`
velocity of the source = v
and velocity of the audience = u.
So apparent change in frequency = Doppler shift (`(Deltan)`
`(v+u)/(V-v) n`
When the source of sound remains stationary, v = 0 .
When the audience MOVES towardes the source,
`Deltan_(1) =u/V n`
When the audience is stationary, u = 0.
when the source moves towards the audience with the same velocity (i.e., v = u).
`Deltan_(2) =u/(V-u) n`
Clearly, `Deltan_(2)GT DELTA n_(1)`


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