1.

Show that, the change in frequency of sound during the motion of the source towards audience is more than that when audience moves towards source with same velocity.

Answer» <html><body><p></p>Solution :Natural frequency of the source `=<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>,` <br/> <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> of sound `=V,` <br/> velocity of the source = v <br/> and velocity of the audience = u. <br/> So apparent change in frequency = Doppler shift (`(Deltan)`<br/> `(v+u)/(V-v) n` <br/> When the source of sound remains stationary, v = 0 . <br/> When the audience <a href="https://interviewquestions.tuteehub.com/tag/moves-1104598" style="font-weight:bold;" target="_blank" title="Click to know more about MOVES">MOVES</a> towardes the source, <br/> `Deltan_(1) =u/V n` <br/> When the audience is stationary, u = 0. <br/> when the source moves towards the audience with the same velocity (i.e., v = u). <br/> `Deltan_(2) =u/(V-u) n` <br/> Clearly, `Deltan_(2)<a href="https://interviewquestions.tuteehub.com/tag/gt-1013864" style="font-weight:bold;" target="_blank" title="Click to know more about GT">GT</a> <a href="https://interviewquestions.tuteehub.com/tag/delta-947703" style="font-weight:bold;" target="_blank" title="Click to know more about DELTA">DELTA</a> n_(1)`</body></html>


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