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Show that, the change in frequency of sound during the motion of the source towards audience is more than that when audience moves towards source with same velocity. |
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Answer» Solution :Natural frequency of the source `=N,` VELOCITY of sound `=V,` velocity of the source = v and velocity of the audience = u. So apparent change in frequency = Doppler shift (`(Deltan)` `(v+u)/(V-v) n` When the source of sound remains stationary, v = 0 . When the audience MOVES towardes the source, `Deltan_(1) =u/V n` When the audience is stationary, u = 0. when the source moves towards the audience with the same velocity (i.e., v = u). `Deltan_(2) =u/(V-u) n` Clearly, `Deltan_(2)GT DELTA n_(1)` |
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