1.

Show that the maximum enzyme catalysed reaction rate will occur for `[H^(+)]_("opt")=sqrt(k_(1)k_(2)` The general pH control enzyme catalysed reaction is `EH_(2)^(2+) hArr EH^(+) hArr E` Only `EH^(+)` is capable for binding substrate and catalysing the desired reaction, `k_(1)=([EH^(+)][H^(+)])/([EH_(2)^(2+)]), k_(2) =([E][H(+)])/([EH^(+)]`

Answer» `k_(1)k_(2)=([E][H^(+)]^(2))/([EH_(2)^(2+)])`
In pH control it may be considered that `[E]~~[EH_(2)^(2+)]`, i.e., enzyme combines almost completely with `H^(+)` ions.
Thus, `k_(1)k_(2)~~[H^(+)],[H^(+)]=sqrt(k_(1)k_(2))`


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