1.

Show that the motion of a particle represented by y= sin omega t- cos omega t is simple harmonic with a period of (2pi)/(omega).

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Displacement `y= sin omega t - cos omega t` <br/> `therefore y= sqrt(2) [(1)/(2) sin omega t- (1)/(sqrt(2)) cos omega t]` <br/> `therefore y= sqrt(2) [cos (pi)/(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)sin omega t - sin (pi)/(4) cos omega t]` <br/> `therefore y= sqrt(2) sin (omega t-(pi)/(4))` <br/> comparing this euqation with general <a href="https://interviewquestions.tuteehub.com/tag/equation-974081" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATION">EQUATION</a> of <a href="https://interviewquestions.tuteehub.com/tag/shm-630759" style="font-weight:bold;" target="_blank" title="Click to know more about SHM">SHM</a> `y= A sin (omega t + phi)`, <br/> Amplitude A= 2 unit <br/> <a href="https://interviewquestions.tuteehub.com/tag/angular-11524" style="font-weight:bold;" target="_blank" title="Click to know more about ANGULAR">ANGULAR</a> frequency, `omega = (2pi)/(T)` <br/> `therefore T= (2pi)/(omega)` <br/> `therefore omega = (2pi)/(T)` <br/> `therefore T= (2pi)/(omega)` <br/> Given function represent SHM with a periodic time `T= (2pi)/(omega)`.</body></html>


Discussion

No Comment Found

Related InterviewSolutions