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Show that the three distinct points (a^2,a) (b^2,b) and (c^2,c) can never be collinear. |
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Answer» Solution :Area of triangle with VERTICES `(a^2,a) (b^2,b)` and `(c^2,c)` is `1/2 {a^2(b-c) + b^2(c-a) + c^2(a-b)}` = (a-b) (b-c) (a-c) which is NEVER equal to ZERO except when a = b = c, hence the points are not collinear. |
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