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Shows that the following functions do not possess maximum or minimum. x^3 |
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Answer» Solution :`y = x^3` `dy./dx = 3x^2, (d^2y/dx^2 = 6x` For extremum `dy/dx = 0 RARR 3x^2 = 0 rArr x = 0` `(d^2y)/dx^2]_(x=0) = 0` Thus the function does not POSSESS a MAXIMUM or a minimum. |
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