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Silicon forms a compound with chlorine in which 5.6 g of silicon is combined with 21.3 og chlorine. Calculate the empirical formula of the compound (Atomic mass : `Si = 28 , Cl = 35.5`) |
Answer» Weight of silicon in the compound `= 5.6 g` Weight of chlorine in the compound `= 21.3 g` Total weight of the compound `= 21.3 + 5.6 = 26.9 g` Percentage of silicon in the compound `= ("Weight of silicon")/("Weright of compound")xx100=((5.6g))/((26.9g))xx100=20.8` Percentage of chlorine in the compound `= ("Weight of chlorine")/("Weight of compound")xx100=((21.3g))/((26.9g))xx100=79.2` Step I. Calculation of the simplest whole number ratios of the elements `{:("Element","Percentage","Atomic mass","Gram atoms (Moles)","Atomic ratio (Molar ratio)","Simplest whole no. ratio"),("Si",20.8,28,(20.8)/(28)=0.74,(0.74)/(0.74)=1,1),("Cl",29.2,35.5,(79.2)/(35.5)=2.23,(2.23)/(0.74)=3,3):}` The simplest whole number ratios of different elements are : `Si : Cl : : 1:3` Step II. Writing the empirical formula of the compound The empirical formula of the compound `= SiCl_(3)` |
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