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Silver (atomic weight `108 g mol^(-1))` has a density of `10.5 g cm^(-3)`. The number of silver atoms on a surfaces of area `10^(-12) m^(2)` can be expressed in scientific notation as `Y xx 10^(-x)`, The value of `x` is ……. |
Answer» Density `= 10.5 g c c^(-1)` This measn `10.5 g` silver is present in `1 cm^(3)`. `(10.5)/(108)` mol silver is present in `1 cm^(3)`. `(10.5)/(108) N` silver atoms present in `1 cm^(3)` `.^(3)sqrt((10.5)/(108) N)` silver atoms present in `1 cm` `(.^(3)sqrt((10.5)/(108) N))^(1//2)` silver atoms present is `1 cm^(2)`. `10^(-12)` is equal to `10^(-8) cm^(2)`. `(.^(3)sqrt((10.5)/(108) N))^(1//2) xx 10^(-8)` silver atoms present in `10^(-12) m^(2)`. On solving, we get `1.5 xx 10^(-7) = Y xx 10^(-x)` `:.x = 7` |
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