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Simple pendulum is executing simple harmonic motion with time period `T`. If the length of the pendulum is increased by `21%`, then the increase in the time period of the pendulum of the increased length is:A. 0.1 sB. 0.2 sC. 0.4 sD. 0.15 s |
Answer» Correct Answer - B `(T_(2))/(T_(1))=sqrt((l_(2))/(l_(1)))=sqrt(1.21)` `therefore (T_(2))/(T_(1))=1.1` `(T_(2)-T_(1))/(T_(1))=0.1` `therefore T_(2)-T_(1)=0.1xx2=0.2s` |
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