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Solve each of the following system of inequations in R 11 – 5x > –4, 4x + 13 ≤ –11 |
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Answer» Given, 11 – 5x > –4 and 4x + 13 ≤ –11 Let us consider the first inequality. 11 – 5x > –4 ⇒ 11 – 5x – 11 > –4 – 11 ⇒ –5x > –15 ⇒ \(\frac{-5x}{5}\) > \(\frac{-15}{5}\) ⇒ –x > –3 ⇒ x < 3 ∴ x ∈ (–∞, 3) ...(1) Now, Let us consider the second inequality. 4x + 13 ≤ –11 ⇒ 4x + 13 – 13 ≤ –11 – 13 ⇒ 4x ≤ –24 ⇒ \(\frac{4x}{4}\) ≤ \(\frac{-24}{4}\) ⇒ x ≤ –6 ∴ x ∈ (–∞, –6] ....(2) From (1) and (2), we get x ∈ (–∞, 3) ∩ (–∞, –6] ∴ x ∈ (–∞, –6] Thus, The solution of the given system of inequations is (–∞, –6]. |
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