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Solve the equation `x^(2)-10x-2=0` by the method of completing the square. |
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Answer» We have `x^(2)-10x-2=0` `implies" "x^(2)-10x=0` `implies" "x^(2)-2xx x xx5+5^(2)=2+5^(2)" "["adding "5^(2)" on both sides"]` `implies" "(x-5)^(2)=(2+25)=27` `implies" "x-5=+-sqrt(27)=+-3sqrt(3)" "["taking square root on both sides"]` `implies" "x-5=3sqrt(3)" or "x-5=-3sqrt(3)` `implies" "x=(5+3sqrt(3))" or "x=(5-3sqrt(3)).` Hence, `(5+3sqrt(3))` and `(5-3sqrt(3))` are the roots of the given equation. |
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