InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
Solve the following quadratic equations by factorization:\(\frac{x-4}{x-5}+\frac{x-6}{x-7}=\frac{10}{3};x\neq5,7\) |
|
Answer» In factorization, we write the middle term of the quadratic equation either as a sum of two numbers or difference of two numbers such that the equation can be factorized. \(\frac{x-4}{x-5}+\frac{x-6}{x-7}=\frac{10}{3};x\neq5,7\) ⇒ 3(x2 – 11x + 28) + 3(x2 – 11x + 30) = 10(x2 – 12x + 35) ⇒ 4x2 – 54x + 176 = 0 ⇒ 2x2 – 27x + 88 = 0 ⇒ 2x2 – 16x – 11x + 88 = 0 ⇒ 2x(x – 8) – 11(x – 8) = 0 ⇒ (2x – 11)(x – 8) = 0 ⇒ x = 11/2, 8 |
|