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Solve the following quadratic equations by factorization:\(x^2+(a+\frac{1}{a})x+1 = 0\) |
Answer» In factorization, we write the middle term of the quadratic equation either as a sum of two numbers or difference of two numbers such that the equation can be factorized. \(x^2+(a+\frac{1}{a})x+1=0\) ⇒ ax2 +a2x + x + a =0 ⇒ ax(x + a) + 1(x + a) = 0 ⇒ (ax + 1)(x + a) = 0 ⇒ x = -a, -1/a |
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