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Solve the quadratic equation by completing the square. |
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Answer» rong>Question : Solution :We know that,
So, → 2x² - 20x + 48 = 0 → x² - 10x + 24 = 0 → x² - 4x - 6x + 24 = 0 → x(x - 4) - 6x + 24 = 0 → x(x - 5) - 6(x - 4) = 0 → (x - 4)(x - 6) = 0 → (x - 4) = 0 or (x - 6) = 0 → x = 4 or (x - 6) = 0 → x = 4 or x = 6 (Ans.) Alternative method: → 2x² - 20x - 48 = 0 acx² + (ad + bc)x + bd = (ax + b)(CX + d); → 2(x - 6)(x - 4) = 0 if the product of the FACTOR is 0, at least one factor should be 0; → (x - 6) = 0 or (x - 4) = 0 Solve the equation to find x, → x = 6 or x = 4 (Ans.) Hence, the 6 and 4 are the roots of the given quadratic equation.Learn more :1. solve the quadratic equation√3x²+ 4x-7√3=0 by factorisation method 2. The ZEROES of the polynomial x2 + x - 2are 0 2,1 O 2-1 0 2,1 0 -21 |
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