1.

Solve the quadratic equation by completing the square.​

Answer»

rong>Question :

  • Solve the quadratic EQUATION by completing the square. 2x² - 20x + 48 = 0.

Solution :

We know that,

  • A quadratic equation is in the form of ax² + bx + c = 0, where a, b, c are real numbers and a ≠ 0.

So,

→ 2x² - 20x + 48 = 0

→ x² - 10x + 24 = 0

→ x² - 4x - 6x + 24 = 0

→ x(x - 4) - 6x + 24 = 0

→ x(x - 5) - 6(x - 4) = 0

→ (x - 4)(x - 6) = 0

→ (x - 4) = 0 or (x - 6) = 0

→ x = 4 or (x - 6) = 0

x = 4 or x = 6 (Ans.)

Alternative method:

→ 2x² - 20x - 48 = 0

acx² + (ad + bc)x + bd = (ax + b)(CX + d);

→ 2(x - 6)(x - 4) = 0

if the product of the FACTOR is 0, at least one factor should be 0;

→ (x - 6) = 0 or (x - 4) = 0

Solve the equation to find x,

x = 6 or x = 4 (Ans.)

Hence, the 6 and 4 are the roots of the given quadratic equation.

Learn more :

1. solve the quadratic equation√3x²+ 4x-7√3=0 by factorisation method

brainly.in/question/31993921

2. The ZEROES of the polynomial x2 + x - 2are

0 2,1

O 2-1

0 2,1

0 -21

brainly.in/question/31939737



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