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Sound waves of frequency `660 Hz` fall normally on a perfectly reflecting wall. The shortest distance from the wall at which the air particles have maximum amplitude of vibration is ……………… meters. |
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Answer» `c = v lamda` `:. lamda = (c)/(v) = (330)/(660) = 0.5 m` The antinode will be at a distance of `(lamda)/(4)=(0.5)/(4) = 0.125 m`. |
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