1.

squareABCD is a parallelogram vec(AB)=bar(q),vec(AD)=bar(p),angleBAC is on acute angle. From the point B, the perpendicular is drawn on side vec(AD). The vector along with it is vec( r ). Then vec( r ) = …………. .

Answer»

`VEC( r )=3bar(Q)-(3(bar(p).bar(q)))/((bar(p).bar(p)))bar(p)`
`vec( r )=-bar(q)+((bar(p).bar(q)))/((bar(p).bar(p)))bar(p)`
`vec( r )=bar(q)-((bar(p).bar(q)))/((bar(p).bar(p)))bar(p)`
`vec( r )=-3bar(q)+(3(bar(p).bar(q)))/((bar(p).bar(p)))bar(p)`

ANSWER :B


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